Bài giải:

$\overline{a,322}+\overline{0,b54}+\overline{0,6c5}+\overline{0,03d}$

$=a+0,322+\overline{0,b}+0,054+\overline{0,0c}+0,605+\overline{0,00d}+0,03$

$=\overline{a,bcd}+1,011$                                                                     (1)

$\overline{a,0c1}+\overline{1,b1d}.$

$=a+\overline{0,0c}+0,001+1,010+\overline{0,b0d}$

$=(a+\overline{0,0c}+\overline{0,b0d})+(1,010+0001)$

$=\overline{a,bcd}+1,011$                                                                     (2)

So sánh (1) và (2) ta có:

$\overline{a,322}+\overline{0,b54}+\overline{0,6c5}+\overline{0,03d}$ = $\overline{a,0c1}+\overline{1,b1d}.$