Ta có phương trình tiếp tuyến

$y=f'\left( {{x}_{0}} \right)\left( x-{{x}_{0}} \right)+{{y}_{0}}\Rightarrow 2=\frac{5}{{{\left( x+2 \right)}^{2}}}\left( 2-{{x}_{0}} \right)+\frac{2{{\text{x}}_{0}}-1}{{{x}_{0}}+2}$

$\Rightarrow 2{{\left( {{x}_{0}}+2 \right)}^{2}}=5\left( 2-{{x}_{0}} \right)+\left( 2{{\text{x}}_{0}}-1 \right)\left( {{x}_{0}}+2 \right)$

$\Rightarrow {{x}_{0}}=0\Rightarrow y=\frac{5}{4}x-\frac{1}{2}$