Chọn: Đáp án A

$\begin{align}   & y={{x}^{3}}-3{{x}^{2}}-3x+2,D=\mathbb{R} \\  & \Rightarrow y'=3{{x}^{2}}-6x-3=3({{x}^{2}}-2x-1) \\ \end{align}$

$y'=0\Leftrightarrow {{x}^{2}}-2x-1=0\Leftrightarrow \left[ \begin{align}  & x=1-\sqrt{2} \\  & x=1+\sqrt{2} \\ \end{align} \right.$

$\Rightarrow {{y}_{CD}}=f(1-\sqrt{2})={{(1-\sqrt{2})}^{3}}-3{{(1-\sqrt{2})}^{2}}-3(1-\sqrt{2})+2=-3+4\sqrt{2}\text{ }$