Hướng dẫn:

${{n}_{NaCl}}=\frac{{{m}_{NaCl}}}{{{M}_{NaCl}}}=\frac{7312,5}{58,5}=125\left( mol \right)$

$2NaCl+2{{H}_{2}}O\to C{{l}_{2}}+{{H}_{2}}+2NaOH$

125                 62,5                        (mol)

Theo phương trình ta có: ${{n}_{C{{l}_{2}}}}=\frac{{{n}_{NaCl}}}{2}=\frac{125}{2}=62,5\left( mol \right)$

$\Rightarrow {{V}_{C{{l}_{2}}}}=22,4.{{n}_{C{{l}_{2}}}}=22,4.62,5=1400\left( l \right)$

Chọn đáp án C