Bài giải:

$3\frac{1}{11}\times \frac{27}{46}\times 1\frac{6}{17}\times 2\frac{4}{9}=\frac{34}{11}\times \frac{27}{46}\times \frac{23}{17}\times \frac{22}{9}$

$=\frac{34\times 27\times 23\times 22}{11\times 46\times 17\times 9}=\frac{(17\times 2)\times (9\times 3)\times 23\times (11\times 2)}{11\times (23\times 2)\times 17\times 9}$

$=\frac{(11\times 23\times 2\times 17\times 9)\times 2\times 3}{11\times 23\times 2\times 17\times 9}=6$