V = $\frac{90}{100}$(${{V}_{1}}+{{V}_{2}}$)
$\Rightarrow {{V}_{1}}+{{V}_{2}}=V:\frac{90}{100}=0,00009:\frac{90}{100}=0,0001$ (số liệu đề bài sai)
${{m}_{1}}+{{m}_{2}}=0,63$
Mà : $\begin{align} & {{m}_{1}}={{D}_{1}}\times {{V}_{1}}=11300\times {{V}_{1}} \\ & {{m}_{2}}={{D}_{2}}\times {{V}_{2}}=2700\times {{V}_{2}} \\ \end{align}$
$\begin{align} & 11300\times {{V}_{1}}+2700\times {{V}_{2}}=0,63 \\ & 8600\times {{V}_{1}}+2700\times {{V}_{1}}+2700\times {{V}_{2}}=0,63 \\ & 8600\times {{V}_{1}}+2700\times ({{V}_{1}}+{{V}_{2}})=0,63 \\ \end{align}$
${{V}_{1}}+{{V}_{2}}=0,0001$
$\begin{align} & \Rightarrow 8600\times {{V}_{1}}+2700\times 0,0001=0,63 \\ & \Rightarrow {{V}_{1}}=\frac{9}{215000}(c{{m}^{3}}) \\ \end{align}$
${{m}_{1}}={{D}_{1}}\times {{V}_{1}}=11300\times \frac{9}{215000}=0,473kg$
${{m}_{2}}=0,63-0,473=0,157kg$