Hướng dẫn:

${{n}_{{{H}_{2}}Olt}}={{V}_{{{H}_{2}}O}}.{{C}_{{{M}_{{{H}_{2}}O}}}}=1500.0,2=300\left( mol \right)$

                   $2{{H}_{2}}O$  $\xrightarrow{dienphan}$ $2{{H}_{2}}+{{O}_{2}}$

                    300         $\to $      300                                        (mol)

Theo phương trình ta có:

${{n}_{{{H}_{2}}O}}={{n}_{{{H}_{2}}}}=300\left( mol \right)$

$\Rightarrow {{V}_{{{H}_{2}}}}=22,4.{{n}_{{{H}_{2}}}}=22,4.300=6720\left( l \right)$ 

$\Rightarrow $ Chọn đáp án D