Hướng dẫn:

${{n}_{{{H}_{2}}}}=\frac{{{V}_{{{H}_{2}}}}}{22,4}=\frac{3,36}{22,4}=0,15\left( mol \right)$

$Fe+{{H}_{2}}S{{O}_{4loang}}\to FeS{{O}_{4}}+{{H}_{2}}\uparrow $

            0,15      $\leftarrow $              0,15               (mol)

Theo phương trình ta có: ${{n}_{{{H}_{2}}}}={{n}_{{{H}_{2}}S{{O}_{4}}}}=0,15\left( mol \right)$

$\Rightarrow {{V}_{{{H}_{2}}S{{O}_{4}}}}=\frac{{{n}_{{{H}_{2}}S{{O}_{4}}}}}{{{C}_{{{M}_{{{H}_{2}}S{{O}_{4}}}}}}}=\frac{0,15}{0,01}=15\left( l \right)$

$\Rightarrow $ Chọn đáp án C