Hướng dẫn:

$\begin{align}  & CuS{{O}_{4}}+2NaOH\to Cu{{(OH)}_{2}}\downarrow +N{{a}_{2}}S{{O}_{4}} \\ & x\xrightarrow[{}]{}2x\xrightarrow[{}]{}x \\ & CuS{{O}_{4}}+Ca{{(OH)}_{2}}\to Cu{{(OH)}_{2}}\downarrow +CaS{{O}_{4}}\downarrow  \\ & y\xrightarrow[{}]{}y\xrightarrow[{}]{}y\xrightarrow[{}]{}y \\\end{align}$

Theo đầu bài ta có:

$\begin{align}  & x+y=0,065 \\ & 98x+98y+136y=8,41 \\\end{align}$  $\Rightarrow $ $x=0,05;y=0,015$ mol

${{n}_{NaOH}}=2x=2,0,05=0,1mol$

                     $\Rightarrow $ Chọn đáp án D.