Hướng dẫn:

${{n}_{{{C}_{2}}{{H}_{5}}OH}}=\frac{{{m}_{{{C}_{2}}{{H}_{5}}OH}}}{{{M}_{{{C}_{2}}{{H}_{5}}OH}}}=\frac{552}{46}=12\left( mol \right)$

${{C}_{6}}{{H}_{12}}{{O}_{6}}\xrightarrow{30-32{}^\circ C}2{{C}_{2}}{{H}_{5}}OH+2C{{O}_{2}}\uparrow $

 6               $\leftarrow $         12                                   (mol)

Theo phương trình ta có:

${{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}=\frac{{{n}_{{{C}_{2}}{{H}_{5}}OH}}}{2}=\frac{12}{2}=6\left( kmol \right)$

${{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}={{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}.{{M}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}=6.180=1080\left( g \right)=1,08\left( kg \right)$

$\Rightarrow $Chọn đáp án D