Hướng dẫn:

${{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}=\frac{{{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}}{{{M}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}}=\frac{9.1000}{180}=50\left( kmol \right)$

${{C}_{6}}{{H}_{12}}{{O}_{6}}\xrightarrow{30-32{}^\circ C}2{{C}_{2}}{{H}_{5}}OH+2C{{O}_{2}}\uparrow $

  50              $\to $        100                                   (mol)

Theo phương trình ta có:

${{n}_{{{C}_{2}}{{H}_{5}}OH}}=2.{{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}=2.50=100\left( kmol \right)$

${{m}_{{{C}_{2}}{{H}_{5}}OH}}={{n}_{{{C}_{2}}{{H}_{5}}OH}}.{{M}_{{{C}_{2}}{{H}_{5}}OH}}=100.46=4600(kg)=4,6\left( \tan  \right)$

$\Rightarrow $Chọn đáp án D