Hướng dẫn:

${{n}_{C{{H}_{3}}COOH}}={{V}_{C{{H}_{3}}COOH}}.{{C}_{{{M}_{C{{H}_{3}}COOH}}}}=0,1.3=0,3\left( mol \right)$

$C{{H}_{3}}COOH+2{{O}_{2}}\xrightarrow{{{t}^{0}}}2C{{O}_{2}}+2{{H}_{2}}O$

   0,3                         $\to $    0,6       0,6                         mol

Theo phương trình ta có:

${{n}_{C{{O}_{2}}}}=2.{{n}_{C{{H}_{3}}COOH}}=2.0,3=0,6\left( mol \right)$

${{n}_{{{H}_{2}}O}}=2.{{n}_{C{{H}_{3}}COOH}}=2.0,3=0,6\left( mol \right)$

$\sum{{{n}_{hhk}}}={{n}_{C{{O}_{2}}}}+{{n}_{{{H}_{2}}O}}=0,6+0,6=1,2\left( mol \right)$

$\Rightarrow {{V}_{hhk}}=22,4.\sum{{{n}_{hhk}}}=22,4.1,2=26,88\left( l \right)$

$\Rightarrow $Chọn đáp án C