Hướng dẫn:

$C{{H}_{3}}COOH+2{{O}_{2}}\xrightarrow{{{t}^{0}}}2C{{O}_{2}}+2{{H}_{2}}O$                   (1)

0,1                          $\to $    0,2                       ( mol)

${{C}_{2}}{{H}_{5}}OH+3{{O}_{2}}\xrightarrow{{{t}^{0}}}2C{{O}_{2}}+3{{H}_{2}}O$                        (2)

0,12                   $\to $      0,24                         (mol)

Theo phương trình (1) và (2) ta có:

${{n}_{C{{O}_{2}}}}=2.{{n}_{C{{H}_{3}}COOH}}+2.{{n}_{{{C}_{2}}{{H}_{5}}OH}}=2.0,1+2.0,12=0,44\left( mol \right)$

$\Rightarrow {{V}_{C{{O}_{2}}}}=22,4.{{n}_{C{{O}_{2}}}}=22,4.0,44=9,856\left( l \right)$

$\Rightarrow $Chọn đáp án C