Hướng dẫn:

${{n}_{C{{H}_{3}}COOH}}=\frac{{{m}_{C{{H}_{3}}COOH}}}{{{M}_{C{{H}_{3}}COOH}}}=\frac{12}{60}=0,2\left( mol \right)$

$C{{H}_{3}}COOH+NaOH\to C{{H}_{3}}COONa+{{H}_{2}}O$

   0,2           $\to $ 0,2                                             (mol)

Theo phương trình ta có:

${{n}_{NaOH}}={{n}_{C{{H}_{3}}COOH}}=0,2\left( mol \right)$

$\Rightarrow {{V}_{NaOH}}=\frac{{{n}_{NaOH}}}{{{C}_{{{M}_{NaOH}}}}}=\frac{0,2}{2}=0,1\left( l \right)=100\left( ml \right)$

$\Rightarrow $Chọn đáp án C