Hướng dẫn:

${{n}_{{{C}_{2}}{{H}_{4pu}}}}={{n}_{{{C}_{2}}{{H}_{4}}}}.%H=25.80%=20\left( kmol \right)$

${{C}_{2}}{{H}_{4}}+{{H}_{2}}O\to {{C}_{2}}{{H}_{5}}OH$

 20                $\to $ 20                (kmol)

Theo phương trình ta có:

${{n}_{{{C}_{2}}{{H}_{5}}OH}}={{n}_{{{C}_{2}}{{H}_{4}}}}=20\left( kmol \right)$

$\Rightarrow {{m}_{{{C}_{2}}{{H}_{5}}OH}}={{n}_{{{C}_{2}}{{H}_{5}}OH}}.{{M}_{{{C}_{2}}{{H}_{5}}OH}}=20.46=920\left( kg \right)$

$\Rightarrow $Chọn đáp án C