Bài giải:

$M=\left[ \left( \frac{2}{193}-\frac{3}{386} \right).\frac{193}{17}+\frac{33}{34} \right]:\left[ \left( \frac{7}{2001}+\frac{11}{4002} \right).\frac{2001}{25}+\frac{9}{2} \right]$

=$\left( \frac{2}{17}-\frac{3}{34}+\frac{33}{34} \right):\left( \frac{7}{25}+\frac{11}{50}+\frac{9}{2} \right)$

=$\frac{4-3+33}{34}:\frac{14+11+225}{50}$

=$\frac{1}{5}$

Đáp án đúng là C