Bài giải:

$A=\frac{{{4}^{3}}.18-{{3}^{4}}.36}{{{9}^{3}}{{.2}^{2}}-{{2}^{7}}{{.3}^{2}}}$

$=\frac{{{\left( {{2}^{2}} \right)}^{3}}{{.3}^{2}}.2-{{3}^{4}}{{.2}^{2}}{{.3}^{2}}}{{{\left( {{3}^{2}} \right)}^{3}}{{.2}^{2}}-{{2}^{7}}{{.3}^{2}}}$

$=\frac{{{2}^{7}}{{.3}^{2}}-{{2}^{2}}{{.3}^{6}}}{{{2}^{2}}{{.3}^{6}}-{{2}^{7}}{{.3}^{2}}}$

$=\frac{{{2}^{2}}{{.3}^{2}}.\left( {{2}^{5}}-{{3}^{4}} \right)}{{{2}^{2}}{{.3}^{2}}\left( {{3}^{4}}-{{2}^{5}} \right)}$

=-1

Đáp án đúng là D