Bài giải :

( Tính  $\frac{{{3}^{22}}{{.11.3}^{7}}-{{9}^{15}}}{{{\left( {{2.3}^{14}} \right)}^{2}}}=$…… ? )

$\frac{{{3}^{22}}{{.11.3}^{7}}-{{9}^{15}}}{{{\left( {{2.3}^{14}} \right)}^{2}}}=\frac{{{11.3}^{29}}-{{\left( {{3}^{2}} \right)}^{15}}}{{{2}^{2}}.{{\left( {{3}^{14}} \right)}^{2}}}=\frac{{{11.3}^{29}}-{{3}^{30}}}{{{2}^{2}}{{.3}^{28}}}=\frac{{{3}^{28}}\left( 11.3-9 \right)}{{{2}^{2}}{{.3}^{28}}}=\frac{24}{4}=6$