Bài giải:

$\begin{align}  & \left( 1\frac{3}{5}+2\frac{1}{5} \right)\times 1\frac{1}{10}+\left( 1\frac{7}{10}-\frac{4}{5} \right):\frac{3}{7} \\  & =\left( \frac{8}{5}+\frac{11}{5} \right)\times \frac{11}{10}+\left( \frac{17}{10}-\frac{4}{5} \right):\frac{3}{7} \\ \end{align}$

$\begin{align} & =\frac{19}{5}\times \frac{11}{10}+\frac{9}{10}:\frac{3}{7} \\  & =\frac{209}{50}+\frac{21}{10} \\  & =\frac{157}{25} \\ \end{align}$