Ta có:

$\widehat{EID}+\widehat{EIB}={{180}^{0}}$

Thay số: ${{101}^{0}}+\widehat{EIB}={{180}^{0}}\Rightarrow \widehat{EIB}={{180}^{0}}-{{101}^{0}}={{79}^{0}}$

Xét tam giác EIB có:

$\widehat{IEB}+\widehat{EBI}+\widehat{BIE}={{180}^{0}}$

Thay số: ${{90}^{0}}+\widehat{EBI}+{{79}^{0}}={{180}^{0}}$

Suy ra: $\widehat{EBI}={{180}^{0}}-{{90}^{0}}-{{79}^{0}}={{11}^{0}}$

Mặt khác ta có:

$\widehat{ABC}=\widehat{EBD}+\widehat{DBC}={{11}^{0}}+{{24}^{0}}={{35}^{0}}$

Vậy góc ABC có số đo là 35$^{0}$