- Các phản ứng xảy ra:

     $C{{H}_{2}}=C(C{{H}_{3}})-C\text{OO}{{C}_{2}}{{H}_{5}}\ (M)+NaOH\xrightarrow{{{t}^{o}}}C{{H}_{2}}=C(C{{H}_{3}})-C\text{OO}Na\ (Y)+{{C}_{2}}{{H}_{5}}OH\ (X)$

     ${{C}_{2}}{{H}_{5}}OH\ (X)\xrightarrow{{{H}_{2}}S{{O}_{4}}\,,\,\,{{t}^{o}}}C{{H}_{2}}=C{{H}_{2}}\ ({{X}_{1}})+{{H}_{2}}O$

     $nC{{H}_{2}}=C{{H}_{2}}\ ({{X}_{1}})\xrightarrow{{{t}^{o}},\,\,p,\,\,xt}C{{H}_{2}}-C{{H}_{2}}{{}_{n}}$ (P.E)

     $2C{{H}_{2}}=C(C{{H}_{3}})-C\text{OO}Na\ (Y)+{{H}_{2}}S{{O}_{4\,}}\xrightarrow{{}}2C{{H}_{2}}=C(C{{H}_{3}})-C\text{OOH}\ ({{Y}_{1}})+N{{a}_{2}}S{{O}_{4}}$

     $C{{H}_{2}}=C(C{{H}_{3}})-C\text{OOH}\ ({{Y}_{1}})+C{{H}_{3}}OH\overset{{{H}_{2}}S{{O}_{4}}\,,\,\,{{t}^{o}}}{leftrightarrows}C{{H}_{2}}=C(C{{H}_{3}})-C\text{OOC}{{\text{H}}_{3}}\ ({{Y}_{2}})$

     $nC{{H}_{2}}=C(C{{H}_{3}})-C\text{OOC}{{\text{H}}_{3}}\ ({{Y}_{2}})\xrightarrow{xt,p,{{t}^{o}}}C{{H}_{2}}=(C{{H}_{3}})C(C\text{OOC}{{\text{H}}_{3}}){{}_{n}}$ (thủy tinh hữu cơ)