Chọn C.

- Phương trình phản ứng: $\underset{0,2\,mol}{\mathop{C{{H}_{3}}COOH}}\,+\underset{0,25\,mol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\underset{{{t}^{o}}}{\overset{{{H}_{2}}S{{O}_{4}}\ \mathsf{}c}{\longleftrightarrow}}\underset{0,13\,mol}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,+{{H}_{2}}O$

$\Rightarrow H=\frac{{{n}_{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}}{{{n}_{C{{H}_{3}}COOH}}}.100%=$