- Ta có: ${{n}_{\text{m }\!\!{\scriptscriptstyle 3\!/\!{ }_4}\!\!\text{ c x }\!\!\acute{\mathrm{Y}}\!\!\text{ ch}}}=\frac{{{M}_{\text{m }\!\!{}^\text{1}\!\!\text{ ch xenlul }\!\!\ll\!\!\text{ z }\!\!\neg\!\!\text{ }}}}{162}=92592\Rightarrow {{l}_{\text{m }\!\!{}^\text{1}\!\!\text{ ch xenlul }\!\!\ll\!\!\text{ z }\!\!\neg\!\!\text{ }}}={{n}_{\text{m }\!\!{\scriptscriptstyle 3\!/\!{ }_4}\!\!\text{ c x }\!\!\acute{\mathrm{Y}}\!\!\text{ ch}}}{{d}_{m{\scriptscriptstyle 3\!/\!{ }_4}c\text{ x }\!\!\acute{\mathrm{Y}}\!\!\text{ ch}}}=0,046\,(mm)\simeq 4,{{5.10}^{-2}}(mm)$