${{\left( {{C}_{6}}{{H}_{10}}{{O}_{5}} \right)}_{n}}(X)+\text{ }n{{H}_{2}}\text{O}\xrightarrow{{{H}^{+}}}\text{ }n{{C}_{6}}{{H}_{12}}{{O}_{6}}(Y)$ 

     $C{{H}_{2}}OH{{[CHOH]}_{4}}CHO(Y)+B{{r}_{2}}+{{H}_{2}}O\to C{{H}_{2}}OH{{[CHOH]}_{4}}COOH(axit\text{ gluconic)}+2HBr$

     $C{{H}_{2}}OH{{[CHOH]}_{4}}COOH+NaHC{{O}_{3}}\to C{{H}_{2}}OH{{[CHOH]}_{4}}COONa\,(natri\,gluconat)\,\,+\,\,C{{O}_{2}}(Z)\,+\,\,{{H}_{2}}O$

     $6nC{{O}_{2}}(Z)+5n{{H}_{2}}O\xrightarrow{clorophin,\,as}{{\left( {{C}_{6}}{{H}_{10}}{{O}_{5}} \right)}_{n}}(X)$.

Vậy X, Y lần lượt là tinh bột và glucozơ.